Sunday, January 12, 2020

Sasmsung Poter 5 Forces

CHM1022 Lab Report 1 Rate Law of an Iodine Clock Reaction Name: Sashini Naomi Wijesekera Student ID: 23877847 Lab Partner: Zahiya Imam Lab Session: Monday 9. 00am Aim The aim of the experiment is to determine the factors that affect the rate of a reaction, by performing the iodine clock reaction and repeating it changing different initial conditions in order to measure and compare the rate of reaction for each experiment and experimentally determine the rate law. MethodRefer CHM1022 Laboratory Manual, Semester 1 2013. Results and Calculations- Part A- Calculations of rate for one set of conditions 1. n(S2O32-)=CV =0. 0025M*(10/1000)L =2. 50*10-5mol Molar ratio of I2 : S2O32- = 1 : 2 n(I2)=0. 5*n(S2O32-) =0. 5*(2. 50*10-5mol) =1. 25*10-5mol Mean time taken for blue colour to appear = (131sec+135sec+145sec)/3 =137seconds Rate of reaction=n(I2)/t =(1. 25*10-5mol/137sec) =9. 12*10-8mols-1 [H2O2]: C1V1=C2V2 0. 8*1=C2*99 C2=8. 8*10-3M [I-]: C1V1= C2V2 0. 025*10=C2*99 C2=2. 53*10-3M [H30+] : C1V1= C2V2 0. 36*35=C2*99 C2=0. 127M [S2O32-]: C1V1= C2V2 0. 0025*10=C2*99 C2=2. 53*10-4M Part B-Results and calculations B4 (i) n(S2O32-) = 0. 0025*(5/1000) = 1. 25*10-5mol Molar ratio of I2 : S2O32-=1: 2 n(I2)=0. 5*n(S2O32-) n(I2)= 0. 5*(1. 25*10-5) =6. 25*10-6mol B4 (ii) n(S2O32-)= 0. 0025*(20/1000) = 5*10-5mol Molar ratio ofI2: S2O32-=1:2 n(I2)=0. 5*n(S2O32-) n(I2)=0. 5*(5. 0*10-5) =2. 5*10-5mol Part B-Results and calculations | | | | | | |Time/s |n(I2)/mol |Rate/mol s-1 |Concentration/M | | | | | | | | | | | | | | | | | | | | | | | | | |1 |2 |3 |4 |5 |6 |Mean time/s | | | | |B1[H202] (i)higher (ii)lower | 66 | 63 | 61 | 67 | 69 | 60 | 64 | 1. 5*10-5 | (1. 25*10-5)/64=1. 95*10-7 |[H2O2]: C1V1= C2V2 0. 8*2=C2*99 C2=0. 016 | | | 249 | 287 | 242 | 262 | 252 | 260 | 259 | 1. 25*10-5 | (1. 25*10-5)/259=4. 83*10-8 |[H2O2]: C1V1= C2V2 0. 8*0. 5=C2*99 C2=4. 0*10-3 | |B2[I-] (i)higher (ii)lower | 78 | — | 78 | 87 | — | — | 81 | 1. 25*10-5 | (1. 25*10-5)/81=1. 54*10-7 |[I2]: C1V1= C2V2 0. 025*20=C2*99 C2=5. 1*10-3 | | | — | 252 | 288 | 261 | — | — | 267 | 1. 25*10-5 | (1. 25*10-5)/267=4. 68*10-8 |[I2]: C1V1= C2V2 0. 025*5=C2*99 C2=1. 26*10-3 | |B3[H30+] (i)higher (ii)lower | 91 | — | 92 | 94 | — | — | 92 | 1. 25*10-5 | (1. 25*10-5)/92=1. 36*10-7 |[H30+]: C1V1= C2V2 0. 36*70=C2*99 C2=0. 55 | | | 206 | 226 | 221 | 207 | — | — | 215 | 1. 25*10-5 | (1. 25*10-5)/215=5. 81*10-8 |[H30+]: C1V1= C2V2 0. 36*17. 5=C2*99 C2=0. 064 | |B4[S2032-] (i)lower (ii)higher | 61 | 67 | 71 | 69 | — | — | 67 | 6. 25*10-6 | (6. 25*10-6)/67=9. 33*10-8 |[S2032-]: C1V1= C2V2 0. 0025*5. 0=C2*99 C2=1. 26*10-4 | | | 230 | 245 | — | 244 | — | — | 240 | 2. 5*10-5 | (2. 5*10-5)/240=1. 04*10-7 |[S2032-]: C1V1= C2V2 0. 0025*20=C2*99 C2=5. 05*10-4 | |B5(Temp) (i)warmer (ii)colder | 65 | 60 | 58 | — | — | — | 61 | 1. 25*10-5 | (1. 25*10-5)/61=2. 05*10-7 | T=450C | | | — | 288 | 310 | 303 | — | — | 300 | 1. 25*10-5 | (1. 25*10-5)/300=4. 17*10-8 | T=150C | |

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